The last term of an arithmetic sequence is 14 and the ninth term is -1. Find the first four terms of the sequence.

There are multiple answers -- one possible one is -25,-22,-19,-16

Step-by-step explanation:

The formula for an arithmetic sequence is a+(n-1)d, with a being the original value, n being the nth term of the sequence, and d being the distance between terms in the sequence. Since the 9th term is -1, we can say

-1 = a+(9-1)d, so -1 =a+8d. Next, if we use variable y to designate the amount of numbers in the sequence, we have 14=a+(y-1)d. Since we have 3 variables and only 2 equations, we can't figure out, for sure, what a, y, and d are. There are therefore multiple answers. One possible answer is noting that the difference between 14 and -1 is 15, and 3*5 is 15, so we could say that d is 3 and y is 9+5=14. Then, if -1 = 8(3)+a, we can say that -1 -24=a, so a=-25 in this example. Adding by 3, we get the second term to be -22, the third -19, and the fourth -16

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

for exempl this   system of equations   y = x - 3

                                                                y = 2x - 5

look   the line : y = x -3     ( red)

                            the line : y = 2x -5 ( bleus)