Find the values of the sine, cosine, and tangent for angle A

sin = p/h.

cos=b/h

tan =p/b

pythagoras

h^2=p^2+b^2

here

h=5

p= 3

b=4

sin(A)=3/5

cos(A)=4/5

tan(A)=3/4

Step-by-step explanation:

length of the other side is 5 using pythagorean theorem

sin= opposite/hypotenuse

cos= adjacent/hypotenuse

tan= opposite/adjacent

opposite angle A- 3

adjacent angle A- 4

hypotenuse- 5

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

10+4√2 is the answer. i dont have the time to explain.