Compare the process of solving
|x - 11 + 1 < 15 to that of solving
|x - 11 + 1 > 15.

I have solved them but I don't know what to o next

Step-by-step explanation:

1) lx- 11+ 1< 15

+11 on both sides

lx+ 1< 26

-1 on both sides

lx< 25

2) lx-11+1>15

+11 on both sides

lx+1>26

-1 on both sides

lx> 25

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

step-by-step explanation: