Unless otherwise specified, the domain of a function f is assumed to be the set of all real numbers x for which f(x) is a real number. (a) The function k is defined by k(x)=f(x)g(x). Find k′(0).

(b) The function m is defined by m(x)=f(x)2g(x) . Find m′(5) .

(c) Find the value of x for −1 less than x less than 2 such that
f'(x)=h′(x) .

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

the answer is ! ?

did you get the answer?