Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)].

a. a[b(x)] = 3x2 – 21
b. a[b(x)] = 3x2 – 39
c. a[b(x)] = 3x – 21
d. a[b(x)] = 3x − 39

A(x) = 3x - 12
b(x) = x - 9

a(b(x)) = a(x - 9) = 3(x - 9) - 12 = 3x - 27 - 12 = 3x - 39
a(b(x)) = 3x - 39

Ithink the answer is c just trying to others

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