2. If a certain disease is found in 1 out of 12,000 people, what is the probability that there will be at least one person with that disease in a town of 24,000 people

0.865

Step-by-step explanation:

Given that:

Disease is found in 1 out of 12000 people ; probability that disease is found in atleast one out of 24000 people

Using the binomial probability formula :

P(x = x) = nCx * p^x * (1 - p)^(n-x)

p = 1/ 12000 = 0.0000833333

n = 24000

P(x ≥ 1) = p(x = 1) + p(x =2) + ... + p(x = 24000)

In other to save computation time, we can employ the use of an online binomial probability calculator or a Ti-89 calculator :

The result is thus : 0.86467588659

P(x ≥ 1) = 0.865

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

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step-by-step explanation: