The number of adult Americans from a random sample of n adults who support a bill proposing to extend daylight savings time is a binomial random variable. Assume that its probability will be approximated using the normal distribution. Describe the area under the normal curve that will be computed in order to determine the probability that more than Americans support the bill.

Right of X = 635.5

Step-by-step explanation:

By using the normal approximation to the Binomial random variable, we usually make use of continuity correction.

According to the rule of continuity;

P(X ≤ k) becomes  P( X ≤ K + 0.5)

P(X < K) becomes P(X < K - 0.5)

P(X ≥ K) becomes P(X ≥ K - 0.5)

P(X > K) becomes P(X > K + 0.5)

P(X = K) becomes P(K - 0.5 ≤ X ≤ K + 0.5)

From the given question, Assume that we are to determine the probability that more than 635 Americans support the bill.

Then we use the > sign.

∴

P(X > K ) becomes P(X > K + 0.5)

P(X > 635) becomes P(X > 635 + 0.5)

⇒ P(X > 635.5) tot the right.

Right of X = 635.5

addition

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;