A 350-seat movie theater charges $10.50 admission for adults and $7.50 for children. If the theater is full and $3411 is collected, how many adults and how many children are in the audience (Note: You may use any method to solve the problem.)

Hence 262 adults and 88chidren are in the audience

Step-by-step explanation:

Let the number adults be x

Let the number of children be y

If there are 350seats in the theatre then;

x+y =350 1

Also if $10.50was charged for adults and $7.50 for children with total amount of $3411, then;

10.50x + 7.50 y = 3411 2

Solve simultaneously

From 1, x = 350-y

Substitute into 2:

10.50(350-y) +7.50y = 3411

3675-10.5y+7.50y = 3412

3675-3y = 3411

-3y = 3411-3675

-3y = -264

y = 264/3

y = 88

From 3: x = 350-y

x = 350-88

x = 262

Hence 262 adults and 88chidren are in the audience

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