If sin0=4/5, then cos0 =

If sin(theta) = 4/5, what is the value of cos(theta) in quadrant 1?

sin^2(theta) + cos^2(theta) = 1

(4/5)^2 + cos^2(theta) = 1

16/25 + cos^2(theta) = 1

cos^2(theta) = 1 - 16/25

cos^2(theta) = 25/25 - 16/25

cos^2(theta) = (25 - 16)25

cos^2(theta) = 9/25

cos(theta) = sqrt(9/25) ... we are in quadrant I, so cos(theta) > 0

cos(theta) = 3/5

Step-by-step explanation:

Hope it is helpful...

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

step-by-step explanation:

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