a, b, and c represent three different digits. If you add up all of the six two - digit numbers that can be written with these digits, where you don't use the same digit twice in each number, then the sum will be 528. Find these digits.

The answer is 7, 8 and 9. The Two-digit numbers are: ab, ac, ba, bc, ca, cb

The Sum of them is: 10a + b + 10a + c + 10b + a + 10b + c + 10c + a + 10c + b = 528

22a + 22b + 22c = 528

a + b + c = 528/22

a + b + c = 24      The only option of three different digits with the sum of 24 is 7, 8 and 9.

Hope this helps, stay safe, and merry christmas!

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.

its adding 5.5 each time

step-by-step explanation: