If the domain of the function f(x)=2x^2-8 is {-2, 3, 5}, then the range is

{0, 10, 42}

Step-by-step explanation:

The Domain acts like x and the Range acts like y and f(x) = y

f(x) = 2x^2 - 8

f(-2) = 2(-2)^2 - 8

f(-2) = 2(4) - 8

f(-2) = 8 - 8

f(-2) = 0

f(3) = 2(3)^2 - 8

f(3) = 2(9) - 8

f(3) = 18 - 8

f(3) = 10

f(x) = 2x^2 - 8

f(5) = 2(5)^2 - 8

f(5) = 2(25) - 8

f(5) = 50 - 8

f(5) = 42

To check, look at the graph below ---

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step-by-step explanation: