If you were to roll the dice one time what is the probability it will NOT land on a 2?

5 / 6

Step-by-step explanation:

Given that:

Probability that a dice rolled once will not land on 2

Probability = required outcome / Total possible outcomes

Total possible outcomes = (1, 2, 3, 4, 5, 6)

Required outcome = 2

P(not land on 2) = 1 - p(land on 2)

P(land on 2) = 1/6

P(not land on 2) = 1 - 1/6

P(not land on 2) = 5/6