*HELP ASAP WILL MARK BRAINLIEST* Ignore if you don't know Geometry problem: Point D is the incenter of triangleABC, if DE=x^2 and DF= 20-8x, find each of the following

x = 2

DG = 4

Step-by-step explanation:

The thing to know about the incenter of a triangle, is that the segments to each side are equidistant. In other words, they are identical lengths.

This means that ED = FD = GD.

Which means:

DE = DF

x^2 = 20 - 8x

So we need to solve for X. I would solve this using factoring:

Subtract 20 from both sides.

x^2−20=−8x

Add 8x to both sides.

x^2−20+8x=0

Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.

x^2+8x−20=0

Factor the left hand side by grouping. First, the left hand side needs to be rewritten as x^2+ax+bx−20. To find a and b, set up a system to be solved.

a+b=8 ab=1(−20)=−20

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product −20.

(−1,20) (−2,10) (−4,5)

Calculate the sum for each pair.

−1+20=19

−2+10=8

−4+5=1

The solution is the pair that gives sum 8.

a=−2 b=10

Rewrite x^2+8x−20 as (x^2−2x)+(10x−20).

(x^2−2x)+(10x−20)

Factor out x in the first and 10 in the second group.

x(x−2)+10(x−2)

Factor out common term x−2 by using distributive property.

(x−2)(x+10)

To find equation solutions, solve x−2=0 and x+10=0.

x = 2

x = −10

In this case, X is equal to 2 as the solution -10 doesn't make much sense given the context of the problem.

To find DG we just need to plug the solution back into one of the equations and solve:

20 - 8x

20 - 8(2)

20 - 16 = 4

DG = 4

rounding to the nearest thousandth would be 452,000

answer: what are the following choices