B) The sum of the ages of the father and son is 44 years. After 8 years, the age of father will be twice the age of the son. Find their present ages,

Let the present age of father = x years

and the present age of son = y years

according to the first condition

x + y =44 (i)

according to the second condition

x+8 = 2(y+8)

or x+ 8 = 2y + 16

or x- 2y = 8 (ii)

solve the equation (i) & (ii) we get

x + y =44

x- 2y = 8

••••••••••••••••••••••••

3y = 36

or y = 12

put the value of y in equation (i), we get

x + 12 =44

or x = 32

so the present age of father = x =32 years

and the present age of son = y = 12 years.

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

-1   1/6.   you dont subtract the denominators

step-by-step explanation: