Write an equation that is perpendicular to the line y = 5x + 3 that contains point A(0,7).

Step-by-step explanation:

The given equation of line :

y = 5x + 3 ....(1)

The general equation of a line is :

y = mx +b ...(2)

From equation (1) and (2)

Slope, m = 5

The slope of the line perpendicular to this one will have a slope equal to the negative reciprocal such that,

The perpendicular slope = -1/5. It contains point A(0,7).

Put x = 0 and y = 7 in eqution (2)

Hence, required equation that is perpendicular to the line y = 5x + 3 is :

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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a - base

b - exponent

so,