Two defenders and the ball carrier start at the 40-yard line. Defender 1 starts 10 yards away from the ball carrier to the ball carrier’s left. Defender 2 starts 30 yards away from the ball carrier to the ball carrier’s right. Defender 1 runs 1.1 times as fast as the ball carrier. Defender 2 runs 1.25 times as fast as the ball carrier. Will either defender be able to reach the ball carrier before he runs the 40 yards he needs to reach the end zone and score a touchdown? Provide evidence to support your answer. Also wsg

60

step-by-step explanation:

every triangle measures a total of 120 degrees. you have to find angle c. we know that isosceles triangles angles are equal. 60 degrees plus 60 degrees gives you 120.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

combine all like terms then its just a 2 step equation