What is the equation of the line that contains the point (6, -1) and is perpendicular to line whose equation is y = 2x + 1?

Perpendicular = opposite sign and reciprocal slope
2 slope turns into -1/2
Y = -1/2x + b
Plug in point
-1 = -1/2(6) + b
-1 = -3 + b, b = 2
Solution: y = -1/2x + 2

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.