Select ALL of the following points that lie on the graph of f (x) = 7 - 3x

(-1, 10)

(2, 1)

(0, 7)

Step-by-step explanation:

Any points, that makes the equation of the function, f(x) = 7 - 3x, true, is a point that lies on the graph of the function.

Let's check each of the options.

Option 1: (-2, 1).

Plug in x = -2, f(x) = 1 into f(x) = 7 - 3x

1 = 7 - 3(-2)

1 = 7 + 6

1 = 13 (this is not true)

Thus, (-2, 1) is not a point that lies on the graph of the function.

Option 2: (-1, 10).

Plug in x = -1, f(x) = 10 into f(x) = 7 - 3x

10 = 7 - 3(-1)

10 = 7 + 3

10 = 10 (this is true)

Thus, (-1, 10) is a point that lies on the graph of the function.

Option 3: (2, 1).

Plug in x = 2, f(x) = 1 into f(x) = 7 - 3x

1 = 7 - 3(2)

1 = 7 - 6

1 = 1 (this is true)

Thus, (2, 1) is a point that lies on the graph of the function.

Option 4: (0, 7).

Plug in x = 0, f(x) = 7 into f(x) = 7 - 3x

7 = 7 - 3(0)

7 = 7 - 0

7 = 7 (this is true)

Thus, (0, 7) is a point that lies on the graph of the function.

Option 5: (1, 5).

Plug in x = 1, f(x) = 5 into f(x) = 7 - 3x

5 = 7 - 3(1)

5 = 7 - 3

5 = 4 (this is not true)

Thus, (1, 5) is NOT a point that lies on the graph of the function.

yeet

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