What is the equation of the line that is perpendicular to y minus 3 x = 2 and that passes through (6,1)? On a coordinate plane, a line goes through (0, 2) and (1, 5). A point is at (6, 1).
y = one-third x minus 1
y = one-third x + 3
y = negative one-third x + 3
y = negative one-third x minus 1

In the following diagram it is given that dec,ab || dc, ad || eb, and ad is congruent to bc. a)why isn't abc a parallelogram even though it has a pair of parallel sides and a pair of congruent sides b)explain why be must be congruent to bc. further explain what type of triangle this makes triangle abc and what it tells you about angle 1 and angle 2c) finally why must angle 3 be congruent to angle 1? further, explain why we know that angle 3 is congruent to angle 2