*The sum of 5% of one number and 4% of a second number is 44. The sum of 4% of the first number and 5% of the second number is 46. Find the numbers.

The first number be x is 400 and the second number be y is 600.

Given that,

The sum of 5% of one number and 4% of a second number is 44.

The sum of 4% of the first number and 5% of the second number is 46.

We have to find,

The numbers.

According to the question,

Let, the first number be x,

And the second number be y,

Then,

5% of x = 0.05x

4% of y = 0.04y

The sum of 5% of one number and 4% of a second number is 44 then, the equation is,

0.05x + 0.04y = 44

And As the sum of 4% of one number and 5% of a second number is 46 then, the equation becomes,

5% of y = 0.05y

4% of x = 0.04x

0.04x + 0.05y = 46

On solving both the equations multiply both the equation by 100,

From equation 1,

Substitute the value of x in equation 2,

Substitute the value of x in equation 1,

Hence, The first number be x is 400 and the second number be y is 600.

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The numbers are:

Step-by-step explanation:

Let 'x' be the first number

Let 'y' be the first number

5% of x = 5/100x = 0.05x

4% of y = 4/100y = 0.04y

so the equation becomes

0.05x + 0.04y = 44

Also

4% of x = 4/100x = 0.04x

5% of y = 5/100y = 0.05y

so the equation becomes

0.04x + 0.05y = 46

Thus, the system of the equations becomes

0.05x + 0.04y = 44

0.04x + 0.05y = 46

solving the system of the equation

isolate x for 0.05x + 0.04y = 44

Multiply both sides by 100

Divide both sides by 5

simplify

now isolate y for

Divide both sides by 18

Therefore, the numbers are:

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