An architect is trying different dimensions for the room shown below. Write an algebraic expression the architect can use to find the area of the room then find the area when x is 6 m. Show your work.

x² + 12

48m²

Step-by-step explanation:

Find the diagram attached.

The room can be segregated into two rectangles

The area of the room = Area of bottom rectangle + area of the top rectangle

Area of the bottom rectangle = x * (x-3) = x² - 3x

Area of the top rectangle = 3* (4+x) = 12 + 3x

The area of the room = x² - 3x + 12 + 3x

Area of the room = x² + 12

Hence the algebraic expression that the architect can use to find the area of the room is x² + 12

Given x = 6m

The area of the room = x² + 12

The area of the room = 6² + 12

The area of the room = 36 + 12

The area of the room = 48m²

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

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