Derivative of (a^x/Log a)?

a^x.

Step-by-step explanation:

y = a^x / log a

Assuming the log is to the base e:

y = (1/ log a) * a^x

Derivative of a^x:

Let u = a^x

log u = log a^x

log u = x log a

1/u * du/dx = log a

du/dx =  = u * log a

y = (1 / log a) * u

so  dy/du = 1/log a

and dy/dx = dy/du * du/dx

=  (1/log a )* log a u

= u

= a^x.

step-by-step explanation:

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.