Given the functions f(x) = 2x -1 and g(x) = 2-x, find; (25 pts)
a) f(x) + g(x) b) f(x) – g(x)
- f(-5) d) f(x).g(x) e) f(g(x))
c) g(-5)

Please check the explanation.

Step-by-step explanation:

Given

a)

f(x) + g(x) = (2x - 1) + (2 - x)

                = 2x -1 + 2 - x

                = x + 1

b)

f(x) - g(x) = (2x - 1) - (2 - x)

              = 2x - 1 - 2 + x

               = 3x - 3

c)

g(-5) - f(-5)

Putting x = -5 in g(x) = 2 - x

g(x) = 2 - x

g(-5) = 2 - (-5) = 2+5 = 7

Putting x = -5 in f(x) = 2x - 1

f(x) = 2x - 1

f(-5) = 2(-5) - 1

       = -10 - 1

        = -11

Thus,

g(-5) - f(-5) = 7 - (-11) = 7+11 = 18

d)

f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2

e)

f(g(x)) = f(2-x)

          = 2(2-x)-1

          = 4-2x-1

          = 3-2x

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.