Two of the vertices of a rectangle are (6,1) and (7,1) . IF the rectangle has a perimeter of 18 units, then what are the coordinates of its other two vertices

(6 , -9) (7, -9)

Or

(6, 11) (7, 11)

Step-by-step explanation:

Given: Two of the vertices of a rectangle are (6,1) and (7,1)

Perimeter= 18 units

To get the value of "x"

The distance between Two point can be calculated as (6-7)=-1

Then x= -1

We can get the value of "y" by using expression for perimeter,

The perimeter P= 2x+2y=18

= 2(-1)+2y= 18

-2+2y=18

2y=18+2

2y= 20

y=10

The "y" coordinate can move up or can move down

y1=( 1-10)=-9

Or

y2=( 1+10)=11

Hence, the two other points are;

(6 , -9) (7, -9)

Or

(6, 11) (7, 11)

there is no picture

step-by-step explanation:

put up a picture so people can you

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )