A particle moves along the x-axis so that its position at time 1 > 0 is given by x(t) and dx/dt = -10t⁴+9t² + 8t. The acceleration of the particle is zero when t= a. 0.387
b. 0.831
c. 1.243
d. 1.647
e. 8.094

Given:

A particle moves along the x-axis so that its position at time t > 0 is given by x(t).

To find:

The value of t at which acceleration of the particle is zero.

Solution:

We have, x(t) as position function. So, its derivative with respect to t is velocity.

Derivative of velocity with respect to t is acceleration.

Putting a=0, to find the time t at which acceleration of the particle is zero.

Using the graphing calculator, we get t=0.831 is the only real solution of this equation.

Therefore, the correct option is b.

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step-by-step explanation:

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i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.