Please please please help me i’ll mark brainliest

Given:

The graph of a function f(x).

To find:

The solution set for f(x)>0 and f(x)≤0.

Solution:

From the given graph it is clear that, the function intersect the x-axis at 3 points, i.e., x=-4, -3 and -2.

The graph is above the x-axis before -4 and between -3 and -2.

So, the solution set for f(x)>0 is .

The graph is below the x-axis between -4 and -3; and after -2. For f(x)≤0, those values are in the solution set for which f(x)=0, i.e., x-intercepts. So, we use close brackets in the interval notation.

So, solution set for f(x)≤0 is .

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)