Find the perimeter of ABC with vertices A(1,-1), B(1,-5) and C(5,-1)

8+4√2units

Step-by-step explanation:

The perimeter is the sum of lengths around the triangle that is /AB/+/BC/+/AC/

But the length of the line=√(x2-x1)²+(y2-y1)²

/AB/=√(1-1)²+(-5--1)²=√4²=4units

/BC/=√(5-1)²+(-1--5)²=√16+16=√32=4√2 units

/AC/=√(5-1)²+(-1--1)²=√16=4 units

Perimeter=(4+4√2+4)units=8+4√2 units

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