Part A: State the Greatest Common Factor of 12x2y5z and 150x6y5z and 66y9z

Show all work you did to determine the GCF.

Part B: Factor completely 4x2 – 20x +100

Part C: Factor completely. 81x2-64

Part D: State the factoring rule for special cases. (a + b)2 = ??

Part E: State the factoring rule for difference of two squares. a2 – b2 = ??

Step-by-step explanation:

A) 12x² y⁵z = 2² * 3 * x² * y⁵ * z

150x⁶y⁵z    = 5² * 2 * 3 * x⁶ * y⁵ * z

66y⁹z   =   2 * 3 * 11 * y⁹ * z

GCF =  2 * 3 * y⁵ * z = 6y⁵z

B) 4x² - 40x + 100 = (2x)² - 2 * 2x * 10 + 10²

                             = (2x - 10)²

C) 81x² - 64 = (9x)² - 8²             {a² - b² = (a + b)(a - b)}

                   = (9x + 8)(9x - 8)

D) (a + b)² = a²+ 2ab + b²

E) a² - b² = (a + b)(a - b)

Simplifying 4x2y + 12xy2 + 9y3 Reorder the terms: 12xy2 + 4x2y + 9y3 Factor out the Greatest Common Factor (GCF), 'y'. y(12xy + 4x2 + 9y2) Factor a trinomial.

Step-by-step explanation:

Subtracting Perfect Squares · (a+b)(a-b)=a2-b · Example · 4x2-9= · Subtracting Perfect Cubes · a3-b3=(a-b)( · Adding Perfect Cubes · x3+27=(x+3)(x2-3x+9).

ian gonna lie that is way to much

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v