What is an equation of the line that passes through the point (4,-3) and is perpendicular to the line x-2y=2?

2x+y+11=0

Step-by-step explanation:

The equation of given line is x-2y-2=0

Slope of given line is (m1)= - coefficient of x÷coefficient of y

m1= -1÷-2 =1÷2

Let slope of required line be m2.

Since the two lines are perpendicular,

So,

m1×m2= -1

or, 1÷2×m2 = -1

m2 = -2

The required line is passing through (4,-3)

Using two points slope form,

y-y1 = m(x-x1)

or, y-(-3)= -2(x+4)

or, y+3= -2x -8

or, 2x+y+3+8 = 0

2x+y+11 = 0 which is required equation of line.

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.