WILL MARK BRAINLIEST FOR THE BEST ANSWER. PLEASE SHOW ALL WORK NECESSARY. THANKS. The centre circle has a diameter of 3 cm and the difference in the radii of each larger circle is 4 cm. What is the area of the whole target – the area inside the yellow circle?

9514 1404 393

  about 572.6 square centimeters

Step-by-step explanation:

There are 3 circles outside the center one, so the total radius is 3·4 cm = 12 cm more than the radius of the inner circle.

The inner circle has a diameter of 3 cm, so its radius is 1.5 cm. That means the radius of the entire target is 1.5+12 = 13.5 cm.

The area of a circle is given by the formula

  A = πr^2

For a radius of 13.5 cm, the area is ...

  A = π(13.5 cm)^2 = 182.25π cm^2 ≈ 572.6 cm^2

_____

The attachment shows the target drawn to scale.

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.