Defects in computer hard-drives will usually render the entire computer worthless. For a particular model, the percent defective in the past has been 1%. If a sample size of 400 is taken, what would the 95.5% lower control chart limit be?

The 95.5% lower control chart limit be is 0.0005.

Given,

The average fraction percent in the past defective as p = 1%  = 0.01

Sample size N = 400

Then ,

According to the question ,

95.5% deviation = 2x

We have,

x =

We put these values, into the formula,

x =

=

=

= 0.0000245

The LCL = p - 2x

= 0.01 - 0.0000245

= 0.00005

The Lower control chart limit be is 0.00005

For the more information about Standard deviation click the link given below.

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0.00005

Step-by-step explanation:

We have the average fraction defective as p = 1%

= 0.01

N = 100

Then 95.5% deviation = 2σ

From there we have,

σ = √p*(1-p)/n

When we input these values, into the formula, we will have

σ = √0.01(1-0.01)/100

= √0.01(0.99)/100

= √0.000099

= 0.00995

The LCL = p - 2σ

= 0.01 - 0.00995

= 0.00005

lower control chart limit be is 0.00005

associative property hopes this ! : )

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet