In a certain chemical manufacturing process, the daily weight y of defective chemical output depends on the total weight x of all output according to
the empirical formula

y = 0.01x + 0.00003x2

Where x and y are in kilograms. If the profit is RM100 per kilogram of non-
defective chemical produced and the loss is RM20 per kilogram of defective
chemical produced, how many kilograms of chemical should be produced
daily to maximize the total daily profit?

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

the clb she uses is a driver, so its a 2/5 chance she hits a 180-189 yard shot

step-by-step explanation: