A projectile is fired vertically into the air. Its motion is described by h -16t^2 + 320t where h is the projectile's height in feet after t seconds.

A) During what time intervals with the height of the project I’ll be below 1024 feet?

B) During what time intervals will the height of the projectile be above 1024 feet?

C) When will the projectile land back on the ground?

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

54.864 meters

step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right