Here is the pic, pls solve it, I am very bad at these stuff.

About 339.12 (using 3.14)

About 339.29 (Using PI function on a calculator)

It should say on top if you should use 3.14 or the pi function

Step-by-step explanation:

So find the areas of the circle first, the radius is 3 so we square that and times pi becuase circle of area is pi*raidus^2

So you’ll get 9 Pi

Now there are 2 so we double that

Thats 18 Pi

Now the middle, I‘d like to think of t like a soda can, if you slice a line in the middle And flatten out the curve, you’ll get a. Rectangle which is L*W. Now we know one side (15) and now the other side is just the circumfrcne of the circle (Circumfrnce is the pereimtr of the circle). Now Circumfrnce formula is either 2*radius*pi or just pi*diameter. So we only have radius so 3*2 is 6, 6*pi is 6 pi. Now we multiply 6 pi and 15 which is 90 Pi. Now 90 pi + 18 Pi is 108 pi. Now it depend on what the directions asked, if asked to use 3.14 for pi, its about 339.12 but if asked to use pi function, it’s be 339.29. If asked to use other less common ones, use multiply the thing they asked you to use by 108.

i can you with this question sweetie!

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.