Consider the equation 10 2z/3=15. solve the equation for z.
express the solution as a logarithm base-10
z=
approximate the value of z. round your answer to the nearest thousandth
z=

Hi there! :)

Rewrite as a logarithmic equation using this format:

In this instance:

a = 10 (log is by default base 10)

b = 2z / 3

c = 15

Rewrite as the log equation:

Evaluate log (15):

Multiply both sides by 3:

Divide both sides by 2:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !