The slope of cd is 4/3

which segments are perpendicular?

jk , where j is at (1,−2)(1,−2) and k is at (10, −14)(10, −14)

ef , where e is at (4, 1)(4, 1) and f is at (7, 5)(7, 5)

lm , where l is at (−2, 3)(−2, 3) and m is at (−10, 9)(−10, 9)

gf, where g is at (6, 5)(6, 5)and f is at (10, 2)

Perpendicular lines have negative reciprocal slopes. All that means is " flip " the slope and change the sign. So if we have a slope of 4/3, the the negative reciprocal of that is -3/4. So we need a slope of -3/4 for a perpendicular line.

GF
(6,5)(10,2)
slope = (2-5) / (10 - 6) = -3/4there is ur perpendicular line

The answer for this question is 80