Solve for x: 90 - 3/2x < 30. a.) >-20
b.) >-40
c.) x<-40
d.)<-20

all the < or > have a line under them

The answer would be C, hope i helped

Step-by-step explanation:

First you have to get x by itself. So you do 90-90= 0 and 30-90= -60 which gets:

90 - 3/2x < 30       to     -3/2x < -60

Then, you do -3/2 - (-3/2)= 0 and do the same to -60. -60 - (-3/2) = -58.5

which makes it look like      

X = -58.5

-58.5 is a smaller number than -40 which means, when you fill it in for x it works      

-58.5 ≤ -40

P.S. to put a line under the < and > you    (≤ and ≥)   hold option then click on which ever one you need

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: