HELP PLEASEEE!! Which rule below describes the following transformation: J(-2,-2), KO, 1), L(3, 0), M(0, -3)
to
J'(-1, 2), K (1,5), L'(4,4), M'(1,1)
1. T(x, y) → (x + 1. y - 4)
2. T(x, y) = (x - 1, y - 4)
3. T(x, y) → (x + 1, y + 4)
4. T(x, y) = (x - 1. y + 4)

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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step-by-step explanation:

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