How is 6 a solution for 2x^2+4x=3+3x^2

2x^2+4x-3-3X^2=0
simplify 2x^2+4x-3-3x^2 to -x^2+4x-3
-x^2+4x-3=0
Multiply both sides by -1
x^2-4x+3=0
Factor x^2-4x+3
1. Ask: Which two number add up to -4 and multiply to 3.
2. 3 and -1.
3. Rewrite the expression as (x-3)(x-1):
(x-3)(x-1)=0
5Solve for x
1.Ask: when will (x-3)(x-1) equal zero.
2. when x-3=0 or x-1=0.
x=3,1