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Mathematics, 15.12.2020 23:00 chavice

Through: (βˆ’2, 5), parallel to y = βˆ’ 9/2x + 2 * 1 point
y = -9/2x + 4
y = -9/2x - 2
y = -9/2x + 5
y = -9/2x - 4

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Answers: 3

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You know the right answer?
Through: (βˆ’2, 5), parallel to y = βˆ’ 9/2x + 2 * 1 point
y = -9/2x + 4
y = -9/2x - 2
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