A school club wants to collect at least 500 canned goods for a school food drive. The club has already collected 30 canned goods. Part A
If 10 club members each collect the same number of canned goods, which inequality represents the minimum number of canned goods, n, each
club member must collect for the club to meet the goal?
10n +30<500
10n + 30 500
30n + 10 < 500
30n + 10 > 500

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

i’m here for points.

95.03 is the answer. hope this !