Of the following sets, which represents a function? Situation A = {student's name, all the colors that the student likes}

Situation B = {student's name, the student's favorite math teacher}

a. Only A

b. Only B

c. Both A and B

d. Neither A nor B

Situation B is a function.

Step-by-step explanation:

We know that,

A function is a relation in which every element in the domain i mapped to a unique element in the co-domain.

That is, every element in the domain must have a unique image.

So, we see that,

Situation A = {student's name, all the colors that the student likes}

Here, the students can have more than one color which they like.

Thus, this relation is not a function.

Situation B = {student's name, the student's favorite math teacher}

Here, the students can have only one favorite math teacher.

So, this relation is a function.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: