Jim Tree pays for shipping on the basis of weight. He knows weight is normally distributed so he can use the standard normal distribution. He decides to weigh 1,000 randomly trees in his shipment. Next, he calculates the mean and
standard deviation of their weights. He finds the mean is 30 lbs and the standard deviation is 10 lbs. Now, Jim uses the
normal distribution table to calculate the number of trees in each segment of the distribution.
Standard Deviation
% from table No. of trees out of 1,000
O to +1 (30 to 40 lbs)
34%
+1 to +2 (40 to 50 lbs) 13.7%
137
+2 to +3 (50 to 60 lbs) 2.3%
Totals
50%
500

answer: #1 ads up by 8 and i don't know #2

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.

its very big question plz make it small