What is the solution to the system of equations below? y = negative one-third x + 6 and x = –6 (–6, 8) (–6, 4) (8, –6) (4, –6)

here is your mark brainliest

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

d is the only accurate one

step-by-step explanation: