For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 37 beats per minute, the mean of the listed pulse rates is x=71.0 beats per minute, and their standard deviation is s=18.2 beats per minute. a. What is the difference between the pulse rate of 37 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 37 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 37 beats per minute significant?

See below.

Step-by-step explanation:

(a) Difference = 71 - 37 = 34 beats/minute.

(b) Number of standard deviations = 34 /18.2 = 1.868.

(c) z score = (x - m )/ s     where m = mean and s = standard deviation

= (37 - 71) / 18.2 = -1.868.

(d)  This  z score lies between -2 and 2 so  a pulse rate of 37 is not significant.

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.