Bus A and Bus B leave the bus depot at 5 pm. Bus A takes 30 minutes to complete its route once and bus B takes 35 minutes to complete its route once. If both buses continue to repeat their route, at what time will they be back at the bus depot together?

8:30 pm

Step-by-step explanation:

Bus A and Bus B leave the bus depot at 5 pm. Bus A takes 30 minutes to complete its route once and bus B takes 35 minutes to complete its route once. If both buses continue to repeat their route, at what time will they be back at the bus depot together?

We solve the above question using the Lowest Common Multiple Method.

We find the Multiples of 30 minutes and 35 minutes

Multiples of 30:

30, 60, 90, 120, 150, 180, 210, 240, 270

Multiples of 35:

35, 70, 105, 140, 175, 210, 245, 280

Therefore,

LCM(30, 35) = 210

The Lowest Common Multiple = 210. This means that bus A and bus B will be back at the same depot together after 210 minutes.

We add 210 minutes to 5pm

5 pm + 210 minutes

= 5 pm + 3 hours 30 minutes

= 8:30 pm

Bus A and Bus B will be back at the depot together by 8:30 pm.

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get