A bouncing toy reaches a height of 64 inches at its first peak, 48 inches at its second peak, and 36 inches at its third peak. Which explicit function represents the geometric sequence of the heights of the toy? f(x) = 48(Five-sixths) Superscript x minus 1
f(x) = 48(three-fourths) Superscript x minus 1
f(x) = 64(three-fourths) Superscript x minus 1
f(x) = 64(Five-sixths) Superscript x minus 1

The correct option is;

f(x) = 64(three-fourths)Superscript x minus 1

Step-by-step explanation:

The first peak height that the bouncing toy reaches = 64 inches

The second peak height that the bouncing toy reaches = 48 inches

The third peak height that the bouncing toy reaches = 36 inches

Therefore, given that the sequence has a common ratio, r = 48/64 = 36/48 = 3/4

The first term of the sequence, a = The first peak height reached = 64

The xth term of the geometric sequence with general form, xth term = ar⁽ˣ⁻¹⁾

The xth term of the geometric sequence, f(x), is therefore, given as follows;

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.