A3.00 kg block moving 2.09 m/s right hits a 2.22 kg block moving
392 m/s left. Afterward, the
3.00 kg block moves 1.11 m/s left
Find the momentum of the 2.22 kg
block afterwards.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225

the answer will be b x² +x-1

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,