Felix graphed a system of equations that had no solution. The first equation he graphed was y = {c - 7. PLEASE HELP What was the second equation he graphed? Answer
A y = 3x + 2
B 3y - I= -21
Cy- 2 = {(x + 1)
Dy - 3x = -7

Choice C

Step-by-step explanation:

First when we are looking for a system of equations that has no solution we are looking for two lines that won't intersect and the only lines that would never intersect are parallel lines.

Ok so what we are looking for is an equation with the same slope but different y-intercept. A parallel line should go at the same rate like the other line but shouldn't start at the same point.

Analysing Choice A:

We just said that the slope has to be the same so this one can't be it.

Analysing Choice B:

For this one we have to put it in slope-intercept-form.

So we see that the slope is the same for this one and and the y-intercept is also the same which is NOT what we need so on tho the next one.

Analysing Choice C:

For this one we also have to put it in slope-intercept-form.

We see that the slope are the same and the y-intercept are different so this is the one we are looking for.

Sorry but for the sake of time I won't analyze choice D.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this