15) An arrow is shot upward and outward from the top of a 83-foot cliff, with an initial velocity of 132 feet per second. The height of the arrow t seconds after
launch is given by the equation ℎ = −16
2 + 132 + 83.
a) At what time does the arrow reach its maximum altitude? Round to the
nearest second.
b) What is the maximum altitude?

its not b

step-by-step explanation:

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)